Drop a useless 'if'

This condition has been checked at the beginning of the function.

Noticed this in the code coverage report.

kconfig_hardened_check/__init__.py

@@ -142,7 +142,6 @@ def print_checklist(mode, checklist, with_results):
             fail_suppressed = ' (suppressed in output)'
         if mode == 'show_fail':
             ok_suppressed = ' (suppressed in output)'
-        if mode != 'json':
         print(f'[+] Config check is finished: \'OK\' - {ok_count}{ok_suppressed} / \'FAIL\' - {fail_count}{fail_suppressed}')